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100p^2-144p=0
a = 100; b = -144; c = 0;
Δ = b2-4ac
Δ = -1442-4·100·0
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-144}{2*100}=\frac{0}{200} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+144}{2*100}=\frac{288}{200} =1+11/25 $
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